Ferrari (RACE) Total Current Liabilities (2014 - 2015)
Ferrari (RACE) posted Total Current Liabilities of $1.83 billion for the quarter ended Dec 31, 2015, compared with $271,214 a year earlier.
Analysis
Ferrari (RACE) Total Current Liabilities (2014 - 2015) Analysis & Trends
As of Dec 31, 2015, Ferrari's Total Current Liabilities came in at $1.85 billion.
- In prior years, Ferrari's Total Current Liabilities was $271,214 in the year ended Dec 31, 2014.
Peer Set
Peer Comparison
| # | Company | Market Cap | Enterprise Value | Gross Profit (Qtr) | Total Current Liabilities (Qtr) |
|---|---|---|---|---|---|
| 1 | Tesla | 1,216.24 Bn | 1,042.27 Bn | 4.75 Bn | 35.43 Bn |
| 2 | General Motors | 75.35 Bn | -31.16 Bn | 7.33 Bn | 96.83 Bn |
| 3 | Ferrari | 69.70 Bn | 62.19 Bn | 1.18 Bn | - |
| 4 | Ford Motor | 48.22 Bn | -94.27 Bn | 6.08 Bn | 107.93 Bn |
| 5 | Honda Motor | 44.40 Bn | -105.41 Bn | 8.46 Bn | 63.48 Bn |
| 6 | Toyota Motor | 24.11 Bn | -382.39 Bn | 20.95 Bn | 205.27 Bn |
| 7 | Magna International | 18.41 Bn | 12.44 Bn | 1.61 Bn | - |
| 8 | Rivian Automotive | 17.72 Bn | -5.59 Bn | 179.00 Mn | 3.62 Bn |
| 9 | Stellantis | 12.89 Bn | -151.76 Bn | 5.55 Bn | 99.58 Bn |
| 10 | Li Auto | 11.86 Bn | -37.05 Bn | 417.98 Mn | 8.03 Bn |
API Access
Ferrari Total Current Liabilities API
Pull this series into your own models, spreadsheets and apps with the Business Quant
Historical Metrics API. The request below matches the chart above — change the
frequency, period or values and it follows. Swap YOUR_API_KEY for your own key.
https://data.businessquant.com/historic?slug=total-current-liabilities&ticker=RACE&period=max&api_key=YOUR_API_KEY
import requests
url = "https://data.businessquant.com/historic"
params = {"slug": "total-current-liabilities", "ticker": "RACE", "period": "max", "api_key": "YOUR_API_KEY"}
data = requests.get(url, params=params).json()
const res = await fetch("https://data.businessquant.com/historic?slug=total-current-liabilities&ticker=RACE&period=max&api_key=YOUR_API_KEY");
const data = await res.json();