Minerals Technologies (MTX) Amortization - Intangibles (2014 - 2015)
Minerals Technologies (MTX) posted Amortization - Intangibles of $8.2 million for FY2016, up 5.1% from $7.8 million in FY2015.
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Analysis
Minerals Technologies (MTX) Amortization - Intangibles (2014 - 2015) Analysis & Trends
- Business Quant data shows MTX's Amortization - Intangibles at $7.8 million in FY2015 (+62.5%) and $4.8 million in FY2014.
Peer Set
Peer Comparison
| # | Company | Market Cap | Enterprise Value | Gross Profit (Qtr) |
|---|---|---|---|---|
| 1 | Rio Tinto | 181.90 Bn | 148.03 Bn | - |
| 2 | Southern Copper | 169.19 Bn | 148.06 Bn | 2.90 Bn |
| 3 | Newmont | 121.55 Bn | 89.73 Bn | 4.03 Bn |
| 4 | Ternium | 108.92 Bn | 73.97 Bn | 941.02 Mn |
| 5 | Freeport-Mcmoran | 100.46 Bn | 96.62 Bn | 2.19 Bn |
| 6 | Agnico Eagle Mines | 91.62 Bn | 91.62 Bn | 2.43 Bn |
| 7 | Barrick Mining | 68.12 Bn | 52.86 Bn | 2.90 Bn |
| 8 | Nucor | 53.04 Bn | 43.58 Bn | 2.03 Bn |
| 9 | ArcelorMittal | 50.74 Bn | 31.77 Bn | - |
| 10 | Minerals Technologies | 2.04 Bn | 739.32 Mn | 133.80 Mn |
Historic Data
Download Data
Historic Data
| Date | Value |
|---|---|
| Dec 31, 2015 | 2.00 Mn |
| Sep 27, 2015 | 2.00 Mn |
| Dec 31, 2014 | 1.90 Mn |
| Sep 28, 2014 | 1.90 Mn |
API Access
Minerals Technologies Amortization - Intangibles API
Pull this series into your own models, spreadsheets and apps with the Business Quant
Historical Metrics API. The request below matches the chart above — change the
frequency, period or values and it follows. Swap YOUR_API_KEY for your own key.
https://data.businessquant.com/historic?slug=amortization-intangibles&ticker=MTX&period=max&api_key=YOUR_API_KEYimport requests
url = "https://data.businessquant.com/historic"
params = {"slug": "amortization-intangibles", "ticker": "MTX", "period": "max", "api_key": "YOUR_API_KEY"}
data = requests.get(url, params=params).json()const res = await fetch("https://data.businessquant.com/historic?slug=amortization-intangibles&ticker=MTX&period=max&api_key=YOUR_API_KEY");
const data = await res.json();