EUDA Health Holdings (EUDA) Return on Capital Employed [ROCE] (2022 - 2023)
EUDA Health Holdings (EUDA) posted Return on Capital Employed [ROCE] of -83.35% for FY2023, down 38.23 percentage points from -45.12% in FY2022.
Analysis
EUDA Health Holdings (EUDA) Return on Capital Employed [ROCE] (2022 - 2023) Analysis & Trends
- Business Quant data shows EUDA's Return on Capital Employed [ROCE] at -45.12% in FY2022.
Peer Set
Peer Comparison
| # | Company | Market Cap | Enterprise Value | Gross Profit (Qtr) | ROCE (Qtr) |
|---|---|---|---|---|---|
| 1 | HCA Healthcare | 106.37 Bn | 104.21 Bn | 17.03 Bn | 27.97% |
| 2 | Natera | 45.03 Bn | 40.66 Bn | 513.47 Mn | -12.46% |
| 3 | Labcorp Holdings | 30.12 Bn | 28.22 Bn | 1.11 Bn | 9.44% |
| 4 | Quest Diagnostics | 28.44 Bn | 26.52 Bn | 1.04 Bn | 11.30% |
| 5 | Guardant Health | 20.93 Bn | 16.54 Bn | 236.15 Mn | -33.03% |
| 6 | BrightSpring Health Services | 14.41 Bn | 11.29 Bn | 518.55 Mn | 11.79% |
| 7 | Tempus AI | 14.27 Bn | 11.42 Bn | 266.70 Mn | -14.14% |
| 8 | Encompass Health | 13.98 Bn | 14.44 Bn | 1.54 Bn | 13.69% |
| 9 | Davita | 11.35 Bn | 10.22 Bn | 1.13 Bn | 14.26% |
| 10 | EUDA Health Holdings | 27.71 Mn | 26.55 Mn | - | - |
API Access
EUDA Health Holdings Return on Capital Employed [ROCE] API
Pull this series into your own models, spreadsheets and apps with the Business Quant
Historical Metrics API. The request below matches the chart above — change the
frequency, period or values and it follows. Swap YOUR_API_KEY for your own key.
https://data.businessquant.com/historic?slug=return-on-capital-employed-%5Broce%5D&ticker=EUDA&period=max&api_key=YOUR_API_KEY
import requests
url = "https://data.businessquant.com/historic"
params = {"slug": "return-on-capital-employed-[roce]", "ticker": "EUDA", "period": "max", "api_key": "YOUR_API_KEY"}
data = requests.get(url, params=params).json()
const res = await fetch("https://data.businessquant.com/historic?slug=return-on-capital-employed-%5Broce%5D&ticker=EUDA&period=max&api_key=YOUR_API_KEY");
const data = await res.json();