Endovia Health Sciences (EDVA) Long-Term Deferred Tax (2017 - 2019)
Endovia Health Sciences (EDVA) posted Long-Term Deferred Tax of $120,000 for Q4 2019, down 19.5% from $149,000 a year earlier.
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Analysis
Endovia Health Sciences (EDVA) Long-Term Deferred Tax (2017 - 2019) Analysis & Trends
- In prior years, Endovia Health Sciences' Long-Term Deferred Tax was $149,000 in FY2018 (-32.3%) and $220,000 in FY2017.
Peer Set
Peer Comparison
| # | Company | Market Cap | Enterprise Value | Gross Profit (Qtr) |
|---|---|---|---|---|
| 1 | Coca Cola | 399.08 Bn | 385.55 Bn | 8.42 Bn |
| 2 | Coca Cola Femsa Sab De Cv | 198.07 Bn | 198.07 Bn | 2.06 Bn |
| 3 | Pepsico | 183.70 Bn | 141.47 Bn | 13.75 Bn |
| 4 | Monster Beverage | 91.30 Bn | 79.55 Bn | 1.42 Bn |
| 5 | Diageo | 51.63 Bn | 31.70 Bn | - |
| 6 | Ambev | 51.46 Bn | 36.75 Bn | 2.06 Bn |
| 7 | Coca-Cola Europacific Partners | 50.42 Bn | 43.09 Bn | - |
| 8 | Keurig Dr Pepper | 46.94 Bn | 42.98 Bn | 3.07 Bn |
| 9 | Constellation Brands | 22.50 Bn | 22.05 Bn | 1.39 Bn |
| 10 | Endovia Health Sciences | 477,205.70 | -693,793.30 | - |
Historic Data
Download Data
Historic Data
| Date | Value |
|---|---|
| Dec 31, 2019 | 120,000.00 |
| Dec 31, 2018 | 149,000.00 |
| Dec 31, 2017 | 220,000.00 |
API Access
Endovia Health Sciences Long-Term Deferred Tax API
Pull this series into your own models, spreadsheets and apps with the Business Quant
Historical Metrics API. The request below matches the chart above — change the
frequency, period or values and it follows. Swap YOUR_API_KEY for your own key.
https://data.businessquant.com/historic?slug=long-term-deferred-tax&ticker=EDVA&period=max&api_key=YOUR_API_KEYimport requests
url = "https://data.businessquant.com/historic"
params = {"slug": "long-term-deferred-tax", "ticker": "EDVA", "period": "max", "api_key": "YOUR_API_KEY"}
data = requests.get(url, params=params).json()const res = await fetch("https://data.businessquant.com/historic?slug=long-term-deferred-tax&ticker=EDVA&period=max&api_key=YOUR_API_KEY");
const data = await res.json();