Anheuser-Busch InBev (BUD) Debt Ratio (2015 - 2026)
Anheuser-Busch InBev's (BUD) Debt Ratio stood at 0.66 in Q2 2026, down 7.5% from 0.72 a year earlier.
Analysis
Anheuser-Busch InBev (BUD) Debt Ratio (2015 - 2026) Analysis & Trends
For FY2025, Anheuser-Busch InBev's Debt Ratio came in at 0.33, down 4.5% from FY2024.
- Across earlier years, Debt Ratio came in at 0.35 in FY2024 (-51.0%), 0.71 in FY2023 (+89.8%), 0.38 in FY2022 (-54.0%) and 0.82 in FY2021 (-6.3%).
- Quarterly Debt Ratio has ranged from 0.33 in Q4 2025 to 0.82 in Q4 2021 over the past five years.
- Peak year-over-year performance for Debt Ratio in the last five years was growth of 89.8% in Q4 2023, against a decline of 54.0% in Q4 2022 at the low end.
Peer Set
Peer Comparison
Historic Data
Download Data
Historic Data
| Date | Value |
|---|---|
| Jun 30, 2026 | 0.66 |
| Dec 31, 2025 | 0.33 |
| Jun 30, 2025 | 0.72 |
| Dec 31, 2024 | 0.35 |
| Jun 30, 2024 | 0.74 |
| Dec 31, 2023 | 0.71 |
| Jun 30, 2023 | 0.75 |
| Dec 31, 2022 | 0.38 |
| Jun 30, 2022 | 0.78 |
| Dec 31, 2021 | 0.82 |
| Jun 30, 2021 | 0.42 |
| Dec 31, 2020 | 0.87 |
| Jun 30, 2020 | 0.47 |
| Dec 31, 2019 | 0.44 |
| Jun 30, 2019 | -0.45 |
| Dec 31, 2018 | 0.48 |
| Jun 30, 2018 | -0.76 |
| Dec 31, 2017 | 0.47 |
| Jun 30, 2017 | 0.43 |
| Dec 31, 2016 | 0.48 |
API Access
Anheuser-Busch InBev Debt Ratio API
Pull this series into your own models, spreadsheets and apps with the Business Quant
Historical Metrics API. The request below matches the chart above — change the
frequency, period or values and it follows. Swap YOUR_API_KEY for your own key.
https://data.businessquant.com/historic?slug=debt-ratio&ticker=BUD&period=max&api_key=YOUR_API_KEY
import requests
url = "https://data.businessquant.com/historic"
params = {"slug": "debt-ratio", "ticker": "BUD", "period": "max", "api_key": "YOUR_API_KEY"}
data = requests.get(url, params=params).json()
const res = await fetch("https://data.businessquant.com/historic?slug=debt-ratio&ticker=BUD&period=max&api_key=YOUR_API_KEY");
const data = await res.json();