Telomir Pharmaceuticals (TELO) Other Operating Expenses (2023 - 2024)
Telomir Pharmaceuticals (TELO) reported Other Operating Expenses of $370,500 for FY2024, down 79.0% from $1.77 million in FY2023.
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Analysis
Telomir Pharmaceuticals (TELO) Other Operating Expenses (2023 - 2024) Analysis & Trends
- According to Business Quant data, Other Operating Expenses came in at $1.77 million in FY2023.
Peer Set
Peer Comparison
| # | Company | Market Cap | Enterprise Value | Gross Profit (Qtr) |
|---|---|---|---|---|
| 1 | Eli Lilly | 1,136.97 Bn | 1,105.55 Bn | 19.71 Bn |
| 2 | Johnson & Johnson | 619.72 Bn | 538.25 Bn | 17.26 Bn |
| 3 | AbbVie | 503.40 Bn | 476.52 Bn | 12.70 Bn |
| 4 | Merck | 370.15 Bn | 324.53 Bn | 12.21 Bn |
| 5 | Novartis Ag | 298.64 Bn | 262.63 Bn | 11.24 Bn |
| 6 | Astrazeneca | 261.07 Bn | 234.76 Bn | 12.86 Bn |
| 7 | Amgen | 237.00 Bn | 192.40 Bn | 7.24 Bn |
| 8 | Gilead Sciences | 191.24 Bn | 165.43 Bn | 6.22 Bn |
| 9 | Pfizer | 170.31 Bn | 116.96 Bn | 10.94 Bn |
| 10 | Telomir Pharmaceuticals | 62.66 Mn | 42.09 Mn | - |
Historic Data
Download Data
Historic Data
| Date | Value |
|---|---|
| Mar 31, 2024 | 370,500.00 |
| Dec 31, 2023 | 479,550.00 |
| Sep 30, 2023 | 589,400.00 |
| Jun 30, 2023 | 698,600.00 |
API Access
Telomir Pharmaceuticals Other Operating Expenses API
Pull this series into your own models, spreadsheets and apps with the Business Quant
Historical Metrics API. The request below matches the chart above — change the
frequency, period or values and it follows. Swap YOUR_API_KEY for your own key.
https://data.businessquant.com/historic?slug=other-operating-expenses&ticker=TELO&period=max&api_key=YOUR_API_KEYimport requests
url = "https://data.businessquant.com/historic"
params = {"slug": "other-operating-expenses", "ticker": "TELO", "period": "max", "api_key": "YOUR_API_KEY"}
data = requests.get(url, params=params).json()const res = await fetch("https://data.businessquant.com/historic?slug=other-operating-expenses&ticker=TELO&period=max&api_key=YOUR_API_KEY");
const data = await res.json();