Pinnacle Financial Partners (PNFP) EBT (2025 - 2026)
Pinnacle Financial Partners' EBT came in at $419 million for Q2 2026, up 114.9% from $195 million a year earlier and up 121.7% from the prior quarter.
Pinnacle Financial Partners (PNFP) EBT (2025 - 2026) Analysis & Trends
Over the trailing twelve months to Jun 30, 2026, Pinnacle Financial Partners reported EBT of $973 million.
Peer Comparison
| # | Company | Market Cap | Enterprise Value | Gross Profit (Qtr) | EBT (Qtr) |
|---|---|---|---|---|---|
| 1 | Jpmorgan Chase | 890.60 Bn | 920.07 Bn | - | 27.52 Bn |
| 2 | Banco Santander Chile | 421.74 Bn | 541.68 Bn | - | 279.77 Bn |
| 3 | Bank Of America | 385.85 Bn | -1,990.22 Bn | - | 11.57 Bn |
| 4 | Hsbc Holdings | 345.94 Bn | 345.99 Bn | - | - |
| 5 | Morgan Stanley | 303.15 Bn | -205.95 Bn | - | 7.35 Bn |
| 6 | Royal Bank Of Canada | 279.82 Bn | 130.57 Bn | - | 5.56 Bn |
| 7 | Mitsubishi Ufj Financial | 274.62 Bn | -1,313.87 Bn | 10.89 Bn | 7.02 Bn |
| 8 | Goldman Sachs | 267.07 Bn | -3,290.04 Bn | - | 8.56 Bn |
| 9 | Wells Fargo & Company | 243.79 Bn | 245.93 Bn | - | 8.05 Bn |
| 10 | Pinnacle Financial Partners | 14.12 Bn | -6.01 Bn | - | 419.00 Mn |
Historic Data
| Date | Value |
|---|---|
| Jun 30, 2026 | 419.00 Mn |
| Mar 31, 2026 | 189.00 Mn |
| Jun 30, 2025 | 195.00 Mn |
| Mar 31, 2025 | 170.00 Mn |
Pinnacle Financial Partners EBT API
Pull this series into your own models, spreadsheets and apps with the Business Quant
Historical Metrics API. The request below matches the chart above — change the
frequency, period or values and it follows. Swap YOUR_API_KEY for your own key.
https://data.businessquant.com/historic?slug=ebt&ticker=PNFP&period=max&api_key=YOUR_API_KEY
import requests
url = "https://data.businessquant.com/historic"
params = {"slug": "ebt", "ticker": "PNFP", "period": "max", "api_key": "YOUR_API_KEY"}
data = requests.get(url, params=params).json()
const res = await fetch("https://data.businessquant.com/historic?slug=ebt&ticker=PNFP&period=max&api_key=YOUR_API_KEY");
const data = await res.json();