Lineage Cell Therapeutics (LCTX) Price to FCF (2022)
Lineage Cell Therapeutics' (LCTX) Price to FCF was 308.06 for Q4 2022, up 367.6% from the prior quarter.
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Analysis
Lineage Cell Therapeutics (LCTX) Price to FCF (2022) Analysis & Trends
Dating back to Q1 2022, Lineage Cell Therapeutics' Price to FCF record includes 4 quarters.
- Per Business Quant data, the three quarters before Q4 2022 came in at 65.88 (Q3 2022), 70.99 (Q2 2022) and 48.48 (Q1 2022).
Peer Set
Peer Comparison
| # | Company | Market Cap | Enterprise Value | Gross Profit (Qtr) |
|---|---|---|---|---|
| 1 | Eli Lilly | 1,082.65 Bn | 1,051.23 Bn | 19.71 Bn |
| 2 | Johnson & Johnson | 623.68 Bn | 542.21 Bn | 17.26 Bn |
| 3 | AbbVie | 459.43 Bn | 432.59 Bn | 12.70 Bn |
| 4 | Merck | 354.80 Bn | 309.23 Bn | 12.21 Bn |
| 5 | Novartis Ag | 269.16 Bn | 225.03 Bn | 11.24 Bn |
| 6 | Astrazeneca | 244.40 Bn | 217.97 Bn | 12.86 Bn |
| 7 | Amgen | 220.17 Bn | 175.57 Bn | 7.24 Bn |
| 8 | Gilead Sciences | 183.05 Bn | 157.16 Bn | 6.22 Bn |
| 9 | Pfizer | 160.27 Bn | 107.22 Bn | 10.94 Bn |
| 10 | Lineage Cell Therapeutics | 227.62 Mn | 26.02 Mn | - |
Historic Data
Download Data
Historic Data
| Date | Value |
|---|---|
| Dec 31, 2022 | 308.06 |
| Sep 30, 2022 | 65.88 |
| Jun 30, 2022 | 70.99 |
| Mar 31, 2022 | 48.48 |
API Access
Lineage Cell Therapeutics Price to FCF API
Pull this series into your own models, spreadsheets and apps with the Business Quant
Historical Metrics API. The request below matches the chart above — change the
frequency, period or values and it follows. Swap YOUR_API_KEY for your own key.
https://data.businessquant.com/historic?slug=price-to-fcf&ticker=LCTX&period=max&api_key=YOUR_API_KEYimport requests
url = "https://data.businessquant.com/historic"
params = {"slug": "price-to-fcf", "ticker": "LCTX", "period": "max", "api_key": "YOUR_API_KEY"}
data = requests.get(url, params=params).json()const res = await fetch("https://data.businessquant.com/historic?slug=price-to-fcf&ticker=LCTX&period=max&api_key=YOUR_API_KEY");
const data = await res.json();