Diageo (DEO) Accumulated Expenses (2011 - 2013)
Diageo's Accumulated Expenses came in at $1.54 billion for fiscal Q4 2013 (quarter ended Jun 30, 2013), up 11.2% from $1.39 billion a year earlier.
Diageo (DEO) Accumulated Expenses (2011 - 2013) Analysis & Trends
At the end of FY2013 (ended Jun 30, 2013), Diageo's Accumulated Expenses was $1.57 billion, up 13.5% from FY2012.
- Going back by fiscal year, Accumulated Expenses was $1.39 billion in FY2012.
Peer Comparison
| # | Company | Market Cap | Enterprise Value | Gross Profit (Qtr) |
|---|---|---|---|---|
| 1 | Coca Cola | 416.85 Bn | 405.33 Bn | 8.45 Bn |
| 2 | Diageo | 246.91 Bn | 229.06 Bn | - |
| 3 | Coca Cola Femsa Sab De Cv | 201.88 Bn | 201.88 Bn | 37.08 Bn |
| 4 | Pepsico | 195.70 Bn | 153.66 Bn | 13.75 Bn |
| 5 | Anheuser-Busch InBev | 154.67 Bn | 154.67 Bn | 27,528.00 |
| 6 | Monster Beverage | 88.75 Bn | 85.98 Bn | 1.40 Bn |
| 7 | Coca-Cola Europacific Partners | 52.79 Bn | 46.01 Bn | - |
| 8 | Keurig Dr Pepper | 51.16 Bn | 50.63 Bn | 3.53 Bn |
| 9 | Ambev | 43.82 Bn | 28.73 Bn | 2.14 Bn |
| 10 | Constellation Brands | 24.62 Bn | 24.46 Bn | 1.39 Bn |
Historic Data
| Date | Value |
|---|---|
| Jun 30, 2013 | 271.60 Mn |
| Dec 31, 2012 | 286.08 Mn |
| Jun 30, 2012 | 274.67 Mn |
| Dec 31, 2011 | 294.44 Mn |
Diageo Accumulated Expenses API
Pull this series into your own models, spreadsheets and apps with the Business Quant
Historical Metrics API. The request below matches the chart above — change the
frequency, period or values and it follows. Swap YOUR_API_KEY for your own key.
https://data.businessquant.com/historic?slug=accumulated-expenses&ticker=DEO&period=max&api_key=YOUR_API_KEY
import requests
url = "https://data.businessquant.com/historic"
params = {"slug": "accumulated-expenses", "ticker": "DEO", "period": "max", "api_key": "YOUR_API_KEY"}
data = requests.get(url, params=params).json()
const res = await fetch("https://data.businessquant.com/historic?slug=accumulated-expenses&ticker=DEO&period=max&api_key=YOUR_API_KEY");
const data = await res.json();