Avricore Health (AVCRF) Free Cash Flow (2009 - 2026)
Avricore Health (AVCRF) posted Free Cash Flow of -$344,768 for Q2 2026.
Analysis
Avricore Health (AVCRF) Free Cash Flow (2009 - 2026) Analysis & Trends
For the trailing twelve months through Jun 30, 2026, Free Cash Flow at Avricore Health was $196,455; for FY2025, it came in at -$502,033.
- In prior years, Avricore Health's Free Cash Flow was $601,499 in FY2024, -$267,686 in FY2023, -$1.25 million in FY2022 and -$1.07 million in FY2021.
- The Q2 2026 figure stands as the lowest quarterly Free Cash Flow since Q2 2023.
Peer Set
Peer Comparison
Historic Data
Download Data
Historic Data
| Date | Value |
|---|---|
| Jun 30, 2026 | -344,768.12 |
| Mar 31, 2026 | -16,474.21 |
| Mar 31, 2025 | 199,497.22 |
| Mar 31, 2024 | 358,200.23 |
| Dec 31, 2023 | -70,018.13 |
| Sep 30, 2023 | -61,668.31 |
| Jun 30, 2023 | -371,782.54 |
| Mar 31, 2023 | 233,915.66 |
| Dec 31, 2022 | -334,081.52 |
| Sep 30, 2022 | -450,799.25 |
| Jun 30, 2022 | -186,977.40 |
| Mar 31, 2022 | -153,942.18 |
| Dec 31, 2021 | -379,558.95 |
| Sep 30, 2021 | -212,401.22 |
| Jun 30, 2021 | -249,292.38 |
| Mar 31, 2021 | -226,974.94 |
| Dec 31, 2020 | -270,451.97 |
| Sep 30, 2020 | -135,350.92 |
| Jun 30, 2020 | -186,765.86 |
| Mar 31, 2020 | -321,839.34 |
API Access
Avricore Health Free Cash Flow API
Pull this series into your own models, spreadsheets and apps with the Business Quant
Historical Metrics API. The request below matches the chart above — change the
frequency, period or values and it follows. Swap YOUR_API_KEY for your own key.
https://data.businessquant.com/historic?slug=free-cash-flow&ticker=AVCRF&period=max&api_key=YOUR_API_KEY
import requests
url = "https://data.businessquant.com/historic"
params = {"slug": "free-cash-flow", "ticker": "AVCRF", "period": "max", "api_key": "YOUR_API_KEY"}
data = requests.get(url, params=params).json()
const res = await fetch("https://data.businessquant.com/historic?slug=free-cash-flow&ticker=AVCRF&period=max&api_key=YOUR_API_KEY");
const data = await res.json();